Find the titles of courses in the Comp. Sci. department that have 3 credits. select title from course where dept name = ’Comp. Sci.’ and credits = 3 b.Find the names of all students who have taken at least one Comp. Sci. course; make sure there are n … View the full answer
Use GROUP BYand HAVING COUNTto get all the students that have taken more than five courses: SELECT student_id FROM yourtable WHERE Semester = .... GROUP BY student_id HAVING COUNT(DISTINCT Course) > 5
To get the number of students you can count the number of rows that query returns: SELECT COUNT(*) AS total FROM ( SELECT student_id FROM yourtable WHERE Semester = .... GROUP BY student_id HAVING COUNT(DISTINCT Course) > 5 )
To get the number of students who are registered for more than 5 courses you do this... SELECT COUNT(*) FROM REGISTRATION WHERE SEMESTER = 'GIVEN SEMESTER' GROUP BY CAMPUS, STUDENT_ID HAVING COUNT(*) > 5; You need to group by campus AND student id since student id is repeated for different campuses.
SQL> select * from student1 where 2 student_fname like '%a' and 3 student_lname like '%a'; no rows selected. ... Read my answer again please.More items...•
SELECT statement is used to get name and marks of top three students.SQL query is. SELECT Name, Marks FROM Student s1 where 3 <= (SELECT COUNT(*) FROM Students s2 WHERE s1.marks = s2.marks)SQL (Structured Query Language) ... Functions of SQL (Structured Query Language)
SELECT COUNT(column_name) counts the non-null values of column in the table. The total number of STU_DEPT values in above table are 7 but one of them is null. Since count(column_name) counts non-null values of the given column, thus the output is 6.
coddisc where subjects=('A') AND subjects=('B');
Select subjectid,max(marks) from students group by subjectid;chandinikiran. Answered On : Mar 2nd, 2010.SELECT s1.studentid, s1.subjectid, s2.mks FROM student s1, (SELECT s.subjectid, max(s.marks) as mks from student s group by s.subjectid ) s2WHERE s1.subjectid =s2.subjectid and s1.marks= s2.mksORDER BY s1.studentid.
To get the last record, the following is the query. mysql> select *from getLastRecord ORDER BY id DESC LIMIT 1; The following is the output. The above output shows that we have fetched the last record, with Id 4 and Name Carol.
We will follow the below steps to connect the PostgreSQL database server using the pgAdmin GUI tool:Step1: Launch the pgAdmin application. ... Step2: Create a server. ... Step3: Provide the server name. ... Step4: Provide the host and password. ... Step5: Expanding the server. ... Step6: Open the Query tool.More items...
Creating a table in MySQL using pythonImport mysql. connector package.Create a connection object using the mysql. connector. ... Create a cursor object by invoking the cursor() method on the connection object created above.Then, execute the CREATE TABLE statement by passing it as a parameter to the execute() method.
SQL COUNT() FunctionSQL COUNT(column_name) Syntax. The COUNT(column_name) function returns the number of values (NULL values will not be counted) of the specified column: ... SQL COUNT(*) Syntax. The COUNT(*) function returns the number of records in a table: ... SQL COUNT(DISTINCT column_name) Syntax.
A NATURAL JOIN is a JOIN operation that creates an implicit join clause for you based on the common columns in the two tables being joined. Common columns are columns that have the same name in both tables. A NATURAL JOIN can be an INNER join, a LEFT OUTER join, or a RIGHT OUTER join. The default is INNER join.
A Subquery or Inner query or a Nested query is a query within another SQL query and embedded within the WHERE clause. A subquery is used to return data that will be used in the main query as a condition to further restrict the data to be retrieved.
Question:How will you change "Hansen" into "Nilsen" in the LastName column in the Persons Table?A UPDATE Persons SET LastName = 'Nilsen' WHERE LastName = 'Hansen'B UPDATE Persons SET LastName = 'Hansen' INTO LastName = 'Nilsen'C SAVE Persons SET LastName = 'Nilsen' WHERE LastName = 'Hansen'More items...