So we only have two possible outcomes, either heads or tails. So here we toss a coin 10 times. So we have two times two times two times 22 to the 10th power. So that's two times two times 2 10 times or 2 to 10 power, which is equal to 1000 and 24.
Full Answer
Welcome to the coin flip probability calculator, where you'll have the opportunity to learn how to calculate the probability of obtaining a set number of heads (or tails) from a set number of tosses.This is one of the fundamental classical probability problems, which later developed into quite a big topic of interest in mathematics.
Check the probability of flipping a coin 10 times and getting 5 heads? Here is the answer! if i flip a coin 10 times how many times should i get heads
Use the complement method to solve. P(at least once) = 1 - P(no heads) =1 - (1/2)^10=1023/1024 hope that helped
What’s the probability of getting 3 heads and 7 tails if one flips a fair coin 10 times. I just can’t figure out how to model this correctly.
Answer (1 of 9): Traditionally, people have focused on two outcomes: heads or tails. In theory there are other possible outcomes: it might land on its side; it might fly up in the air and never come back down; it might get swallowed by a wormhole in space. But for most people, H/T is good enough....
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For each of the 2 possible outcomes for the first coin toss, there are 2 possible outcomes for the second coin toss. So the total number of possible outcomes for the first two coin tosses is 2×2 = 4.
A coin is tossed eight times. In how many different orders could five heads and three tails occur?
The event with highest probability (0.0889278) is 40 heads and 40 tails.
You start with zero heads with probability 1. At each step, you flip a coin. Each probability is split into two, where for the first one you flipped a head and you add one to the number of heads and halve the probability.
For ten flips, it’s 2^10… which is 1024.
Not surprisingly, the denominator is 2 1000, so the numerator is simply the count of how many of all of the possible sets of 1000 flips has contained within it at least one streak of ten heads. To more digits, the answer is approximately 0.3854497524.
There are two possibilities for each flip (Heads or Tails). You multiply those together to get the total number of unique sequences.
Take a die roll as an example. If you have a standard, 6-face die, then there are six possible outcomes, namely the numbers from 1 to 6. If it is a fair die, then the likelihood of each of these results is the same, i.e., 1 in 6 or 1 / 6. Therefore, the probability of obtaining 6 when you roll the die is 1 / 6. The probability is the same for 3. Or 2. You get the drill. If you don't believe me, take a dice and roll it a few times and note the results. Remember that the more times you repeat an experiment, the more trustworthy the results. So go on, roll it, say, a thousand times. We'll be waiting here until you get back to tell us we've been right all along.
Therefore, the probability of obtaining 6 when you roll the die is 1 / 6. The probability is the same for 3. Or 2. You get the drill. If you don't believe me, take a dice and roll it a few times and note the results. Remember that the more times you repeat an experiment, the more trustworthy the results.
Whether you want to toss a coin or ask a girl out, there are only two possibilities that can occur. In other words, if you assign the success of your experiment, be it getting tails or the girl agreeing to your proposal, to one side of the coin and the other option to the back of the coin, the coin toss probability will determine the answer. It all boils down to getting your hands on a coin that is weighted appropriately.
Tip: You don't need to go from the top to the bottom.
For each of the 2 possible outcomes for the first coin toss, there are 2 possible outcomes for the second coin toss. So the total number of possible outcomes for the first two coin tosses is 2×2 = 4.
A coin is tossed eight times. In how many different orders could five heads and three tails occur?
The event with highest probability (0.0889278) is 40 heads and 40 tails.
You start with zero heads with probability 1. At each step, you flip a coin. Each probability is split into two, where for the first one you flipped a head and you add one to the number of heads and halve the probability.
For ten flips, it’s 2^10… which is 1024.
Not surprisingly, the denominator is 2 1000, so the numerator is simply the count of how many of all of the possible sets of 1000 flips has contained within it at least one streak of ten heads. To more digits, the answer is approximately 0.3854497524.
There are two possibilities for each flip (Heads or Tails). You multiply those together to get the total number of unique sequences.