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An ice skater is spinning with her arms out and is not being acted upon by an external torque. a. When she pulls her arms in close to her body what happens to her angular momentum? b. When she pulls her arms in, what happens to her moment of inertia? c. What happens to her angular speed when she pulls her arms in? d. What happens to her ...
Transcribed image text: (3%) Problem 29: An ice skater is spinning with her arms out and is not being acted upon by an external torque. Status e for View ining 25% Part (a) When she pulls her arms in close to her body what happens to her angular momentum? It increases Olt decreases it remains unchanged It cannot be determined Grade Summary Deductions 0 Potential 1004 …
To increase the rotational velocity of her spin, she pulls her arms in close to her body, reducing her moment of inertia. Angular momentum is conserved, therefore rotational velocity must increase. Then, before coming out of the spin, the skater reduces her rotational velocity by move her arms away from her body, increasing her moment of inertia.
If you're initially rotating with your arms outstretched, then when you draw your arms inward, your moment of inertia decreases. This means that your angular velocity must increase, and you spin faster.
conservation of angular momentum: her moment of inertia is decreased, and so her angular speed must increase to conserve angular momentum. An ice skater performs a pirouette (a fast spin) by pulling in his outstretched arms close to his body.
When she pulls in her arms, her rota- tional potential energy increases as her arms approach the center. Explanation: The kinetic energy of the figure skater, E = 1 2 I ω2 = 1 2 Lω . Since ω increases after she pulls in her arms as mentioned above, the total kinetic energy increases.
A figure skater spins, with her arms outstretched, with angular velocity of ωi. When she moves her arms close to her body, she spins faster. Her moment of inertia decreases, so her angular velocity must increase to keep the angular momentum constant.
Any of the individual angular momenta can change as long as their sum remains constant. This law is analogous to linear momentum being conserved when the external force on a system is zero. must increase to keep the angular momentum constant.
Figure 11.14 (a) An ice skater is spinning on the tip of her skate with her arms extended. Her angular momentum is conserved because the net torque on her is negligibly small. (b) Her rate of spin increases greatly when she pulls in her arms, decreasing her moment of inertia.
Since angular momentum is conserved, if r decreases then p must increase.
Just as in translational motion (where kinetic energy equals 1/2mv2 where m is mass and v is velocity ), energy is conserved in rotational motion. Kinetic energy (K.E.) in rotational motion is related to moment of rotational inertia (I) and angular velocity (ω): KE=12Iω2 KE = 1 2 I ω 2 .
The force due to friction produces an internal torque, which does not affect the angular momentum of the system.
The principle of the conservation of angular momentum holds that an object's angular momentum will stay the same unless acted upon by an outside force. This explains why a figure skater spins faster when she tucks her arms in close to her body.
The work she does to pull in her arms results in an increase in rotational kinetic energy.
Angular momentum is conserved when net external torque is zero, just as linear momentum is conserved when the net external force is zero.