· a) The probability that a student will do homework regularly and also pass the course = P(H n P) = 0.57. b) The probability that a student will neither do homework regularly nor will pass the course = P(H' n P') = 0.12. c) The two events, pass the course and do homework regularly, aren't mutually exclusive. Check Explanation for reasons why.
What is the probability that a student will neither do homework regularly nor will pass the course? (Round your answer to 2 decimal places.) Are the events “pass the course” and “do homework regularly” mutually exclusive? No, because of P (B | A) ≠ P (B).No because of P (A ∩ B) ≠ 0.Yes because P (B | A) = P (B).Yes because of P (A ∩ B) = 0.
Use two decimal digits. You can put this solution on YOUR website! The probability that neither occur is the complement of the event that A or B occurs. So we will first calculate P (A or B) P (A or B) = P (A) + P (B) - P (A and B) But since they are mutually exclusive, P (A and B) = 0 P (A or B) = P (A) + P (B) - P (A and B) P (A or B) = P (A) + P (B) - 0 P (A or B) = P (A) + P (B) P (A or B) = 0.21 …
94E. 95E. 96E. Dr. Miriam Johnson has been teaching accounting for over 20 years. From her experience, she knows that 60% of her students do homework regularly. Moreover, 95% of the students who do their homework regularly generally pass the course. She also knows that 85% of her students pass the course. a.
It is given that the probability that students do homework regularly , p (A)= 0.6
The points in the table lie on a line. Find the slope of the line. a table with 2 rows and 4 columns the top row is 0,1,2,3 and the bottom is -1,0,1,2
A probability distribution of a continuous random variable X gives the probability that X takes on a particular value x, P (X=x). T or F.
A. The probability of rolling a 2 on a single die is one in six.
Joint probability for two independent events is the product of the individual probabilities.
B. The order in which objects are selected does not matter in permutations