So the correct option is 'four'.
1 Answer. One type by AABBCCDD & 16 type by individual Aa Bb Cc Dd (24 = 16).
The number of different possible gametes produced by the diploid genotype (AaBbCcDdEe) is 2 x 2 x 2 x 2 x 2 = 32 (2 for each pair of heterozygous genes).
four typesExplanation: AaBbCc will produce four types of gametes which are as follows – ABC, AbC, aBC, abC. The number of gametes formed depends on the number of heterozygous alleles present in the given genotype.
The given genotype AaBbCcDd is heterozygous for 4 genes and can make 24= 16 types of gametes. Thus, the correct answer is option D.
After fertilisation, the F1 heterozygote will be formed i.e YyRr (yellow and round). On selfing F1 we get two possible combinations i.e YR, Yr, yR, yr. Therefore four types of gametes are formed in the ratio of 1:1:1:1. Thus, the correct answer is option D.
A yy genotype produces only y gametes.
So the correct option is 'four'.
Hints For Biology 101 Exam #4No. of homologous chromosome pairs (heterozygous genes)No. of different gametes from each parent1 (Aa X Aa)2 (21)2 (AaBb X AaBb)4 (22)3 (AaBbCc X AaBbCc)8 (23)4 (AaBbCcDd X AaBbCcDd)16 (24)5 more rows
A self fertilizing trihybrid plant forms 8 different gametes and 64 different zygotes.