a pilot wishes to fly on a course of 70 when the

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Expert Answer

Step 1 We have v → P G, the velocity of the plane relative to the ground, (due west) v → P A, the velocity of the plane relative to the air (320km/h), and v → A G, the velocity of the air relative to the ground (80km/h, due south). v → P G = v → P A + v → A G. Step 2 a) sin ⁡ θ = v A G v P A = 80 k m h 320 k m h θ = 14 ∘, north of west. b) Pythagorean theorem (right triangle): v P G = v P A 2 − v A G 2 = ( 320 k m h) 2 − ( 80 k m h) 2 = 310 k m h..

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